# Tackling ‘time and distance’ problems (SI and constable)

This article is in continuation to the last article on preparation for the Sub-Inspector of Police recruitment exam. Here are some practice questions and solutions on the Time and Distance topic.

1. In a 500 metres race, B starts 45 metres ahead of A, but A wins the race while B is still 35 metres behind. What is the ratio of the speeds of A to B assuming that both start at the same time?

Solution:

The time is same for both A and B.

Let Time = x hrs

Distance for ‘A’ = 500 m, Speed of A = 500/x km/hr

Distance for ‘B’ = 500 – (45 +35) = 420 m Speed of B = 420/x km/hr

The ratio of speeds of A and B is A : B = 500/x : 420/x = 25 : 21

2. In a 500 m race, A reaches the final point in 28s and B reaches in 35s. By how much distance does A beats B?

Solution:

Here, we have to find the distance covered by B, after A has finished the race i.e. distance covered by B in (35 – 28 = 7s).

Distance = 500/35 × 7

= 100 m

A beats B by 100 m

3. In a 10 km race. A, B, and C, each running at uniform speed, get the gold, silver, and bronze medals, respectively. If A beats B by 1 km and B beats C by 1 km, then by how many metres does A beat C?

Solution:

If ‘A’ covers 10 km, then ‘B’ covers 9 km in same time.

So the ratio of Speeds of A and B is A:B = 10:9

Similarly the ratio of Speeds of B and C is

B:C = 10:9

So the ratio of Speeds of A, B and C is

A:B:C = 100:90:81

If ‘A’ covers 100 m, then ‘C’ covers 81 m in same time

If ‘A’ covers 10,000 m (10 km) then ‘C’ covers 8100 m in same time. So, A would beat C by 1900 m.

4. A car covers a distance of 480 km in 6 hours and a bike covers a same distance in 8 hours. Find the ratio of speeds of car and bike?

Solution:

Speed of Car: Speed of Bike = 480/6 : 480/8

= 80 : 60 = 4 : 3

5. The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. What was the total distance travelled in 12 hours?

Solution:

The total distance covered by car in 12 hours = 35+37+ 39 + …………12 times

It is in Arithmetic Progression

Here the first term ‘ a’ = 35

Number of terms ‘n’ = 12

Common difference ‘d’ = 2

The sum of ‘n’ terms in AP = n/2 {2a+ (n-1)d}

Required Distance = 12/2 {2 ×35+11×2} = 6 (70+22) = 6 × 92 = 552 km

6. A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?

Solution:

The relative speed of the policeman and thief = 11 – 10 = 1 km/hr

Distance covered in 6 minutes = T × S = (6/60) ×1 = 1/10 km = 100 m

Therefore, the distance between policeman and thief = 200 = 100 = 100 m

**Special live telecast on T-SAT to clarify doubts**

A special programme with Telangana State Level Police Recruitment Board Chairman VV Srinivasa Rao will be telecast live on T-SAT Network channels on May 5.

In view of the notification issued by the State government on recruitment for SI and Constable posts in different wings of Telangana State Police, the special live programme aims to spread awareness among candidates preparing to appear for the recruitment tests. The show will be telecast on T-SAT at Nipuna channel on May 5 from 11 am, T-SAT CEO, R Shailesh Reddy said.

Srinivasa Rao, who has rich experience in the recruitment process for police posts, will be at the T-SAT studios for the show to answer queries and doubts of the job aspirants. During the show, candidates can have their queries and doubts clarified by calling on Phone Nos. 040-23540326, 23540726 or toll-free number 1800 425 4039.

In the last six years, Telangana government has, in two instalments, filled 30,000 police vacancies and now as part of 2022 notifications, the process has been initiated to fill 16,887 posts, said Shailesh Reddy.

For the benefit of candidates preparing to appear for the tests for these posts, the special telecast on syllabus will be done on T-SAT Nipuna channel from 8 am to 10 am and on Vidya channel from 8 pm to 10 pm, starting May 5, he said. This beaming of the special content on preparing for the recruitment tests will continue till the examinations are concluded.

**Hour-long Manomitra:**

Also, to help the aspirants overcome mental stress while preparing for the tests, T-SAT Nipuna will be telecasting an hour-long special programme ‘Manomitra’ on May 5 between 4 pm and 5 pm. According to him, the programme will have a repeat telecast on Sunday from 12 noon to 1 pm.

Shailesh Reddy urged the candidates preparing for the recruitment tests to utilise the special content being telecast on T-SAT Network.

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