Questions on ratio and proportion you should try

This article is in continuation to the last article focusing on the ratio and proportion topic.

Here are some practice questions along with solutions that will help you in preparation for the recruitment tests.

If y/(x – z) = (y+x)/z = x/y then find z : y : x ?
a) 4:3 b) 8:7
c) 3:4 d) 7:8

Ans: b

Solution:
Given, y/(x – z) = (y+x)/z = x/y
yz = xy+x2 − yz − xz ….(1) yz = xy+ x2 – yz – xz ….(1)
Also xy = yx − zxy = yx-z —> x2 − xz = y2 ….(2)
Using (1) and (2), we get yz = xy – yz+y2y2
2yz = xy+y2y2
2z = x+y
Only option (B) satisfies the equation.

At a casino, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and wins at two of the tables, what is the maximum and minimum difference between his earnings?
a) 2500
b) 2000
c) 4000
d) none of these

Ans: c

Solution:
Maximum earning come from his win on the maximum yielding table
A —> 10:1
B —> 20:1
C —> 30:1
i.e, he won on B and C but lost on A
20 × 200+30 × 200 – 1 × 200 = 9800
Minimum earning will be when he won on table A and B and lost on C.
Therefore, 10 ×200+20 × 200 – 1 × 200 = 6000-200 = 5800, difference= 9800 – 5800 = 4000

M Venkat
Director
MVK Publications
Dilsukhnagar
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